Question

at the sea level the composition of dry air is approx approximately and nitrogen is equals to 75.5 percentage oxygen is equals to 23.2 percentage organ is equals to 1.3 % if path total partial pressure at sea level is 1 bar what personal pressure of each component

Answer 1

Answer:

Moles of nitrogen:

N2(N=14X2=28)=75.5/28=2.696

Moles of oxygen

O2(O=16X2=32)=23.2/32=0.725

Moles of Argon

Ar(Ar=40X1=40)=1.3/40=0.0325

Total moles=3.453

partial pressure of nitrogen:

Moles N2/Total moles=partial pressure N2/total pressure

2.696/3.453=X/1(x=partial pressure)

=0.7807atm

partial pressure of oxygen:

Moles O2/total moles=partial pressure O2/total pressure

0.725/3.453=x/1(x=partial pressure)

=0.2099atm

partial pressure of argon:

Moles Ar/total moles=partial pressure Ar/total pressure

0.0325/3.45=x/1(x=partial pressure)

=0.00942atm

Answer 2

Explanation:

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