Question

At the sum 3000 amount to 3993 in 3 years, the interest is compounded annually, then the rate percent
per annum is​

Answer 1

Answer:

It's 1000

hope it's helps

Answer 2

let the rate percentage is =r

now according to the problem

$3993 = 3000(1 + \frac{r}{100} ) {}^{3} \\ = >( \frac{3993}{3000} ) {}^{ \frac{1}{3} } = 1 + \frac{r}{100} \\ = > \frac{r}{100} = 1.1 - 1 \\ = > r = 0.1 \times 100 \\ = > r = 10 \: \: percent$