at the surface of rearth value of g is 48N. At what depth it's weight will become 1/2 of it
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Explanation:
Given that,
Weight of body W=144N
Height h=3R
Radius of earth =R
We know that,
Acceleration due to gravity at the surface of the earth =g
Acceleration due to gravity at height g
′
=3R
Now,
g
′
g
=(
R+h
R
)
2
g
′
g
=(
R+3R
R
)
2
g
′
g
=
16
1
Now, weight at the height
w
w
′
=
mg
mg
′
w
w
′
=
16
1
w
′
=
16
w
w
′
=
16
144
w
′
=9N
Hence, the weight at the height is 9 N
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