Question

at the time of birth of sunita mothers age was 24 years 3 years the age of mother will be twice of her daughter sunitas age she would be then find their present ages​

Answer 1

Answer:

mother=45 years

sunita= 21 years

Step-by-step explanation:

let present ages be:

                    mother = x

                    Sunita = y

at time of birth mother was 24 yrs.

therefore; x=y+24

=> x-y-24=0 (1)

3 years later

         mother's age = x+3

          Sunita's age= y+3

ATQ:

x+3 = 2(y+3)

x+3 = 2y+6

x-2y-3=0 (2)

subtracting equation 2 from 1:

x - y - 24 = 0

x - 2y - 3 = 0

-_______________

y-21=0

y=21

putting value of y

x = y+24

x = 21+24

x=45