at the top of a hill volume of gas balloon is increased to 6/5 times to its volume of the same ballon in the sea level.at sea level the atmospheric pressure is 1 bar .if atmospheric pressure in bar decrease with heigh h in metre as follows p =Patm(1-h/80) the height of hill is
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Answer:
Correct option is A)
At sea level, the pressure is 1 atm. It drops to 0.65 atm.
The diameter is 0.2 m. The radius will be 0.1 m. It changes to x m.
For an ideal gas PV=nRT
Hence, at constant temperature, PV is constant.
PV=P
′
V
′
1×
3
4π
(0.1)
3
=0.65×
3
4π
(x)
3
x=0.1154
2x=0.2308m
Thus, the diameter changes to 0.2308 m
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