Question

At the top of a mountain a thermometer reads 7°C and barometer reads 10 cm of Hg. AT the foot of mountain they lead 27°C and
76 cm of Hg respectively. The ratio of the density of air at the top to that at the bottom of the mountain is​

Answer 1

Answer:

As we know,

PV =

$\frac{w}{m} \times rt$

Therefore-

$d = \frac{w}{ v } = \frac{pm}{rt}$

$\frac{d1}{d2 = }$

$\frac{70 \times m \times r \times 300}{r \times 280 \times 76 \times m}$

Answer is

=0.987

Answer 2

As we know,

PV =

\begin{gathered} \frac{w}{m} \times rt \\ \end{gathered}mw×rt

Therefore-

d = \frac{w}{ v } = \frac{pm}{rt}d=vw=rtpm

\frac{d1}{d2 = }d2=d1

\frac{70 \times m \times r \times 300}{r \times 280 \times 76 \times m}r×280×76×m70×m×r×300

Answer is

= 0.987