at time a particle starts moving along the x-axis. if its kinetic energy increases uniformly with time ???t??? the net force acting on it must be proportional to:
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Answered by
2
It must be proportional to t
TheUrvashi:
heya.. mate please elaborate this answer
Answered by
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⭐hey there!!
Given that:
=> K ∝ t
Removing propornality sign we get,
➡ K = Ct
Where C is any arbitrary constant.
Now we know that K = ½ ×mv²
➡ ½ ×mv² = Ct
➡ mv² = 2Ct
➡ mv = √2Ct
➡ now we also know that : P = mv (momentum)
➡ P = √2ct
Here, We can see that, P ∝ √t
So Force(F) = dP/dt
➡ F ∝ t - ½
♦Hence Force is proportional to negative of half power of time. ✔
_______________________________________
Hope it will help u
Given that:
=> K ∝ t
Removing propornality sign we get,
➡ K = Ct
Where C is any arbitrary constant.
Now we know that K = ½ ×mv²
➡ ½ ×mv² = Ct
➡ mv² = 2Ct
➡ mv = √2Ct
➡ now we also know that : P = mv (momentum)
➡ P = √2ct
Here, We can see that, P ∝ √t
So Force(F) = dP/dt
➡ F ∝ t - ½
♦Hence Force is proportional to negative of half power of time. ✔
_______________________________________
Hope it will help u
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