Question

At time t=0, a ball is dropped
from a bridge onto a roadway
beneath the bridge; One second
later another ball is thrown down
from the same height. The first
ball hits the ground in 2.0 s. The
second ball hits 0.25 seconds later
approximately
what speed is
second ball thrown down?​

Answer 1

Answer:

In first case:

intial velocity (u) = 0

acceleration= 10m/s^2

time taken= 2seconds.

substituting the values in the formula of

S= ut + 1/2 at^2

We get S= 20 meters

so the second ball also travels the same distance as the first ball.

In second case:

S= 20m

acceleration=10m/s^2

time taken= 0.25 seconds

substituting the values in the formula of

S=ut+1/2at^2

We get intial velocity as 78.75 meters/second