Question

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by

−0.50t, in m/s2 for t in seconds. It stops at t =​

Answer 1

Answer:

8sec

Explanation:

As we have U=16m/s V=0 m/s ( at rest) a= -0.50t Using 1st equation of motion V=U+at 0=16+(-50t)dt -16= -50t×t/2 √16×2/50=t

t=8 sec

Answer 2

stops means v=0(final velocity)

u=16 m/s (initial velocity) given

a=-0.50m/s2 (acceleration) given

using v=u+at(first equation of motion)

0=16+(-.50)t

t=32s