Question

At time t=0 , a car moving along straight line has a velocity of 16ms^-1 it slow down with an acceleration of -0.5t ms^2, where t is in seconds

Answer 1

Answer:

answer is 4√2 sec

Explanation:

In this question it is said that

the car was running at the velocity of 16 m/s

and the retardation is -0.5t

where t is the time which is taken by the car to be stopped

now according to the first law of Newton's motion

given

v = 0

u = 16m/s

a = -0.5t

t = t

v = u - at

0 = 16 - 0.5t × t

0.5 t² = 16

t² = 32

t = 4√2

answer