Question

At time t seconds, the velocity (in m/s) of a bead sliding on a wire is given by the equation: v(t)=4$t^{3}$−3$t^{2}$ . Please find the distance, in meters, travelled by the bead between the times t=1s and t=3s

Answer 1

Answer:

3^[237]^

Explanation:

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Answer 2

Answer:

54

Explanation:

s =∫4t^3-3t^2  

 =4t^4/4-3t^3/3

 =t^4-t^3

 =3^4-3^3

 =54