Question

At train in travellng at a speed of 90 km/hr. Brakers are applied so as to produce a uniform acceleration of -0.5m/s 2. Find how far will the train go before it is brought to rest

Answer 1

Answer:

Explanation:When brakes are applied, the uniform acceleration of the train is -0.6 m/s². We have to find the distance covered by the train before it come to rest. So, the train will go 520.8 m before coming to rest.

Answer 2

Answer:

Acceleration a=−0.5m/s 2

Speed v=90km/h=25m/s

Using equation of motion,

v=u+at

Where,

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Finally train will be rest so, final velocity,v=0

0=25−0.5t

25=0.5t

t= 25/0.5

t=50 sec

Again, using equation of motion,

S=ut+ 1/2 at 2

Where, s = distance

v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the equation

Where S is distance travelled before stop

s=25×50− 1/2 ×0.5×(50) 2

s=625 m

So, the train will go before it is brought to rest is 625 m.

Explanation:

Answer by @Missmiracle12 ❤️