Chemistry, asked by av0825161, 6 months ago

At very high pressure, van der Waals gas equation
for one mole of gas reduces to [NCERT Pg. 150]
(1) P=
RT a
V V2
RT a
(2) P=~+
V V2
RT
(3) P=
(4) P=
RT
V + b
V-b​

Answers

Answered by adityadwivedi1709
1

Behaviour of Real Gases. Van der Waals equation at h. ... PV = RT. C. P (V + b ) = RT. D ... Hence the equation (P+V2a​)(V−b)=RT reduces to P(V−b)=RT ... Assume that initially one mole of A was taken in the container. ... and pressure correction for 4.4g of CO2​ kept in 1L Flask a=3.6atmL2mol− and b=0.04Lmol−1.

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