Question

At wch temperature will the translational kinetic energy of H-atom equal to that for H-atom of first line Lyman transition

Answer 1

Answer:

Explanation: Dear student,

$N_{A} = 6*10^{23} \\E=hcv\\Where,\\v =Rz^{2} (\frac{1}{n_{1} ^{2} }-\frac{1}{n_{2} ^{2} })\\Where,n_{1}=1 ,n_{2}=2,z=1\\Hence,\\v=\frac{3}{4}R$$[/tex]</em></p><ul><li><strong>Translational K.E of H-atom:</strong></li><li><strong>[tex]\frac{3}{2}*\frac{R}{N_{A} }*T\\ R = 8.314$

$E=hcv=1.63*10^{-18}J$

By equating transnational K.E to  E

Hence,$T= 7.84*10^{4}K$

Answer 2

Answer:

Gibb xx

Explanation:

ndndjxidjnxn chuteya h to