Question

At what angle a stone should be thrown to get maximum horizontal range

Answer 1

Answer:

for maximum horizontal range of any object,

$\frac{ {u}^{2} \sin(2 \alpha ) }{g} = maximum$

therefore, we know that the maximum value of the sine function is 1 which is obtained at 90° or π/2 radians. hence,

$2 \alpha = \frac{\pi}{2} \\ \alpha = \frac{\pi}{4} = 45 \: degrees$

the stone must be thrown at an angle of 45° with the horizontal.