Question

At what angle do the two forces P+Q and P-Q act so that the resultant is root3P^2+Q^2

Answer 1

Answer:

angle is 60°.hope it helps you

Answer 2

Answer:

60°

Explanation:

R^2 = A^2 + B^2 + 2ABcos @

[√(3P^2+Q^2)]^2 = (P+Q)^2 + (P-Q)^2 + 2(P+Q)(P-Q)cos@

(3P^2+Q^2) = 2P^2 + 2Q^2 +2 (P^2-Q^2)cos@

(P^2-Q^2) = 2( P^2-Q^2)cos@

cos@ = 1/2

hence @= 60°