Question

At what angle in degrees is the first-order maximum for 430-nm wavelength blue light falling on double slits separated by 0.0550 mm

Answer 1

Answer:

Explanation:

Data:

d= 0.0550 mm = 0.0550×10⁻⁶m

m= 1

θ=?

λ= 430 nm = 430×10⁻⁹ m

Formula:

d sin θ=mλ

Solution:

d sin θ=mλ

(0.0550×10⁻⁶m) sin θ= (1)(430×10⁻⁹ m)

(0.0550×10⁻⁶m) sin θ= 430×10⁻⁹ m

sin θ= 430×10⁻⁹ m/0.0550×10⁻⁶m

sin θ=7.818

θ=sin⁻¹(7.818)

θ=4.47°

P.S: The calculator at this stage θ=sin⁻¹(7.818) says maths error so kindly check the question.The procedure is correct but I think there is some mistake in the answer.