Question

At what angle should a body be projected with a velocity 24m/sec just to pass over the

obstacle 16 m high at a horizontal distance of 32 m? Take g= 10 m/sec2.​

Answer 1

Answer:

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Explanation:

ANSWER

Given : u=24 m/s x=24 m y=14 m

Using, equation of trajectory y=xtanθ−

2u

2

cos

2

θ

gx

2

Or 14=24tanθ−

2×24

2

10×24

2

sec

2

θ

Or 14=24tanθ−5(1+tan

2

θ) (∵sec

2

θ=1+tan

2

θ)

Or 5tan

2

θ−24tanθ+19=0

Or tanθ=

2×5

24±

24

2

−4(5)(19)

=

10

24±14

⟹ tanθ=

10

24+14

=3.8