Question

At what angle the force (A+B) and (A-B) show that their resultant √3A^2+B^2​

Answer 1

60°

Explanation:

Assuming that the resultant is (3a²+b²)½.

as, resultant of a and b is [a² +b² +2ab cos (theta)]½

therefore,

[(A+B)² +(A-B)² +2 (A+B) (A-B) cos(theta)]½ = (3a²+b²)½.

squaring both sides and opening brackets

(Rest is solved on picture provided)

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