at what angle to the two forces (P+Q) and (P-Q) act so that the resultant is√3P^2+Q^2
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Explanation:
√3P²+Q²=√(P+Q)²+(P-Q)²+2(P+Q)(P-Q)cosA
3P²+Q²=2(P²+Q²) + 2(P²-Q²)cosA
P² - Q² = 2(P²-Q²) cosA
1/2 = cosA
cos60°=cosA
60°=A
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