Question

at what at what rate percent of compound interest will rupees 625 become 784 in 2 years

Answer 1

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$

$<b><i><font face=Copper black size=4 color=blue>$
Here is your answer
P = Rs 625
A = Rs 784
T = 2 years

As we know the formula

A = P(1+R/100)^t
$784 = 625(1 + \frac{r}{100} ) {}^{2} \\ \frac{784}{625} = (1 + \frac{r}{100} ) {}^{2} \\ ( \frac{28}{25} ) {}^{2} = (1 + \frac{r}{100} ) {}^{2} \\ on \: compairing \\ \frac{28}{25} = 1 + \frac{r}{100} \\ \frac{r}{100} = \frac{28}{25} - 1 \\ \frac{r}{100} = \frac{28 - 25}{25} \\ r = 100 \times \frac{3}{25} \\ r = 4 \times 3 \\ r = 12\%$

Therefore Rate of interest is 12%

$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\: helps\: you}}}}}}}}}}}}}}}$

Answer 2

Rate of percentage is 12 %

Step-by-step explanation:

Given,

Principal, p = 625

Amount, = 784

Time , t = 2 years

Rate, r = ?

We know that,

Amount,  $A = p\times \left( 1 + \frac{r}{100} \right)^2$

$784 = 625\times \left( 1 + \frac{r}{100} \right)^2$

$\left( 1 + \frac{r}{100}\right) = \left( \frac{784}{625} \right)^\frac{1}{2}$

$\left( 1 + \frac{r}{100}\right) = 1.12$

$\frac{100 + r}{100} = 1.12$

100 + r = 112

r = 12 %

Rate of percentage is 12 %