Question

at what% compound interest will 80,000amount to 1,06,480in 3years?​

Answer 1

Explanation:

given

principal=80000

amount=106480

time=3years

Find the rate of compound interest?

according to formula to find r%

$amount= principal(1 + \frac{r}{100} ) {}^{n} \\ = > 106480 = 80000(1 + \frac{r}{100} ) {}^{3} \\ = > \frac{106480}{80000} = (1 + \frac{r}{100} ) {}^{3} \\ = > \frac{1331}{1000} = (1 + \frac{r}{100} ) {}^{3} \\ = > ( \frac{11}{10} ) {}^{3} = (1 + \frac{r}{100} ) {}^{3} \\ = > \frac{11}{10} = \frac{100 + r}{100} \\ = > 100 + r = 110 \\ = > r = 110 - 100 = 10\%$

hence the rate of interest is 10%

I hope it will be helpful so please mark me brainlist