At what concentration of the solute X the solution will be isotonic with 5percent solution of urea
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Answer:
29.1%
Explanation
For solution of P πaV=nRT------1
For solution of urea πbV=nRT-----------2
πa= πb ( Because they are isotonic in nature)
{5/60×0.1 L}×T K ×O.O821= {m/350×0.1} × T K × 0.0821
{5/60× 0.1 L}= m/350
m= 29.1 per 100 gm solution
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