At what depth below the surface of water will pressure be equal to twice the atmospheric pressure? Atmospheric pressure = 10⁵ N/m², density of water is 10³ kg m⁻³ and g = 9.8 ms⁻².
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Depth asked in question will be - 10.2 m
Pressure under water is given by the sum of atmospheric pressure and pressure of fluid.
Further, pressure of fluid will be calculated by the formula given below-
P= rho*g*h
Rho is density of fluid, g is gravity, h depth
Therefore formula for calculation of pressure below water will be-
P'= P+rho*g*h
Given in question is - P'= 2P
P'- P= rho*g*h
2P - P= rho*g*h
P= rho*g*h
h= P/(rho*g)
h= 10^5/(10^3*9.8)
h = 10.2 m
Thus, depth in water at which pressure will be equal to twice the atmospheric pressure is 10.2 m.
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