Question

At what depth below the surface of water will the pressure be equal to 2 atm, if atmosphere pressure is 10⁵pa​

Answer 1

Answer:

h = 10m

Explanation:

Density of water = $10^{3}Kg/m^{3}$

Atmospheric Pressure = $\rho_{0}$

Pressure below water at depth h =  $\rho_{0}$ + $\rho gh$

$\rho$ = density of water

g = acceleration due to gravity

h = depth below water

2$\rho_{0}$ =  $\rho gh$ +  $\rho_{0}$

$10^{5} = 10^{3}(10)h\\h = 10m$

Answer 2

Answer:

Depth=20.44m

Explanation:

Pressure =2× 10⁵ pascal

P=ρ g d(ρ=DENSITY OF WATER and g = gravity

2×10⁵=997 kg/m³× 9.81m/s²×d

Depth=20.44m below water surface

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