at what depth from the surface of earth the value of acceleration due to gravity is reduced by 40% of its value on the surface of earth?
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3840 km below the earth is the answer.
40/100 g= g{1-d/R}
=> d=3/5 x 6400=3840.
40/100 g= g{1-d/R}
=> d=3/5 x 6400=3840.
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