Question

At what Distance a body moving with the velocity 10m/s will be stopped due to friction between the Earth and the body ? If Coff of Friction is 0.4

Answer 1

Answer:

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Explanation:

2.4 is the answer.

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Answer 2

The body will be stopped at a distance of 12.755 m due to friction between the Earth and the body

- The force of friction between the earth and body is given by:

F = μ × R

m × a = μ × m × g

a =  (μ × g)

as the body will stop, it means its acceleration is negative

so, we use a = - (μ × g)

- By using third equation of motion, we get

v² - u² = 2 × a × s

v² - u² = 2 × - (μ × g) × s

0 - (10)² = 2 × -0.4 × 9.8 × s

s = -100 / -7.84

s = 12.755 m