Question

At what distance a ' he' nucleus would have a electric field strength will be 3*10^9 ?

Answer 1

E = [1/4π€]×q/r2

3× 10^9= (9×10^9 × 2×1.6×10^-19 )/r^2

r^2= 9.6* 10^ -19

r almost 10^-9 m