At what distance an object should be placed in front of a convex lens of focal length 12 cm so as to get triple sized image of it?
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f = 12 cm
m = 1
m = v/u = 1
⇒ v = u
Lens formula : 1/v – 1/u = 1/f
Putting the value of v, u and f,
1/u – 1/-u = 1/12 (image distance is negative)
2/u = 1/12
U = 24 cm
The object should be placed at a distance of 24 cm to from the lens (on the left side).
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