at what distance from a concave lens of focal length 20cm a 6cm tall object be placed so as to obtain it's image at 15cm from the lens also calculate the size of the image formed
Answers
Answered by
86
F = 20. [ Sign convention]
Ho = 6cm
V = -15. [ Image formed by concave Mirror is Virtual]
USING LENS FORMULA,
1/F = -1/U+1/V
Put values and solve u will get the the answer.
Using,
M = Hi / Ho = V/U [ Hi is height of Image and Ho is height of object]
Hi/ Ho = V/U
Put VALUES AND SOLVE U WILL GET THE HEIGHT OF IMAGE.
Ho = 6cm
V = -15. [ Image formed by concave Mirror is Virtual]
USING LENS FORMULA,
1/F = -1/U+1/V
Put values and solve u will get the the answer.
Using,
M = Hi / Ho = V/U [ Hi is height of Image and Ho is height of object]
Hi/ Ho = V/U
Put VALUES AND SOLVE U WILL GET THE HEIGHT OF IMAGE.
Answered by
170
Given:
f = 20cm
o = 6 cm
v = 15 cm (image distance)
1\v -1\u = 1\f
1\15 - 1\u = 1\20
1\u = 1\15- 1\20
1\u = 1\60
I\O = V\U
I = 15 × 6 \ 60
I = 1.5 cm
Hope it helps!!
f = 20cm
o = 6 cm
v = 15 cm (image distance)
1\v -1\u = 1\f
1\15 - 1\u = 1\20
1\u = 1\15- 1\20
1\u = 1\60
I\O = V\U
I = 15 × 6 \ 60
I = 1.5 cm
Hope it helps!!
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