At what distance from a concave mirror of focal length 10 cm should an object 2 cm long be placed in order to get erect image of 6 cm tall?
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Heya
Height of the object = 2cm
Height of the image = 6cm
Magnification = hi / ho = -v/u
Magnification = 6/2 = 3cm
-v/u = 3
then -v = 3u
To form an erect image, the object should be placed before focus.
u < 10cm
When u is -1, v is 3
u = -2, v = 6
u = -3, v = 9
u = -4, V = 12
u = -5, v = 15
u = -6, v = 18
u = -7, v= 21
u = -8, v = 24
u = -9, v = 27
Hope it helps!
Height of the object = 2cm
Height of the image = 6cm
Magnification = hi / ho = -v/u
Magnification = 6/2 = 3cm
-v/u = 3
then -v = 3u
To form an erect image, the object should be placed before focus.
u < 10cm
When u is -1, v is 3
u = -2, v = 6
u = -3, v = 9
u = -4, V = 12
u = -5, v = 15
u = -6, v = 18
u = -7, v= 21
u = -8, v = 24
u = -9, v = 27
Hope it helps!
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