at what distance from a concave mirror of focal length 10 cm should an object 2 cm long be placed in order to get an erect image 6 cm tall
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the object should be placed between focus and pole.
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Focal length of concave mirror f = -10 cm
Height of the object ho = 2 cm
Height of the image hi = 6 cm
Magnification m = hi/ho = 6/2 = 3 (erect image)
m = -v/u
3 = -v/u ⇒ v = -3u
Mirror formula: 1/v + 1/u = 1/f
1/(-3u) + 1/u = 1/(-10)
⇒ u = -20/3 = -6.7 cm
So the object should be placed at a distance of 6.7 cm from the pole of the concave mirror (on the left, in front of the mirror).
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Height of the object ho = 2 cm
Height of the image hi = 6 cm
Magnification m = hi/ho = 6/2 = 3 (erect image)
m = -v/u
3 = -v/u ⇒ v = -3u
Mirror formula: 1/v + 1/u = 1/f
1/(-3u) + 1/u = 1/(-10)
⇒ u = -20/3 = -6.7 cm
So the object should be placed at a distance of 6.7 cm from the pole of the concave mirror (on the left, in front of the mirror).
I hope that my answer helped you
if you like my answer then mark me as brainliest please
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