at what distance from a concave mirror of focal length 10CM should an object 2 cm long be place in order to get and erect image 6 cm tall?
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Answer:
u=-13.33cm
Explanation:
f=-10cm
o=2cm
i=6cm
m=I/o=3cm
v=?,u=?
v/u=3cm
v=3u
1/f= 1/v+1/u
so u= -13.33cm
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