At what distance from a concave mirror of focal length 10cm should an object 2 cm long the place in order to get an erect image 6 CM tall?
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Answer: -6.7 cm
Explanation:
Focal length of concave mirror f() = -10 cm
Height of the object (ho) = 2 cm
Height of the image (hi) = 6 cm
To find: Distance of object from mirror=?
So Magnification (m) = hi/ho = 6/2 = 3 (erect image)
m = -v/u
3 = -v/u
v = -3u
Mirror formula: 1/v + 1/u = 1/f
1/(-3u) + 1/u = 1/(-10)
u = -20/3 = -6.7 cm
So At -6.7cm distance from a concave mirror of focal length 10cm should an object 2cm long be placed in order to get an erect image 6cm tall.
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