at what distance from a concave mirror of focal length 10cm should an object 2cm long be placed in order to get an erect image 6 cm tall?
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Answered by
4
Ur answer follows below
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Janadeen:
V shud find u nd then v
There is a change
sorry but i cant see the change
There is a change
C the 2nd pic plz
2nd is the right one not 1st
cant see the 2 pic
Am sry but I have updated
I can c though
There are 2 pics
Answered by
4
hey friend
we have m =h1/H2=-v/u
also using mirror formula
1/v=1/f-1/u
so v=uf/u-f
now putting this in m =h1/H2=-v/u
h1/H2=-f/u-f=6/2=3
so we get
-f/u-f=3
now, -f=3u-3f
so -10=3u-30
-40=3u
u=-40/3=-13.33cm
we have m =h1/H2=-v/u
also using mirror formula
1/v=1/f-1/u
so v=uf/u-f
now putting this in m =h1/H2=-v/u
h1/H2=-f/u-f=6/2=3
so we get
-f/u-f=3
now, -f=3u-3f
so -10=3u-30
-40=3u
u=-40/3=-13.33cm
its 6.66
Ha wrong hi
yrr
just a moment
i'll check
ook
i guess its right........but maybe u r correct
plz.check
simmikumari plz check n tell if possible
simmi???????
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