Question

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At what distance from a concave mirror of focal length 10cm , should ab object 3cm high be placed , so that 6cm high erect image is formed
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Answer 1

Step-by-step explanation:

So At -6.7cm distance from a concave mirror of focal length 10 cm should an object 2 cm long be placed in order to get an erect image 6 cm tall.

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Answer 2

Answer:

Given

Focal length of concave mirror (f) = -10 cm

Height of the object (ho) = 2 cm

Height of the image (hi) = 6 cm

We need to find the object distance

So we know that

Magnification m = hi/ho

hi/ho = 6/2

hi/ho = 3 (erect image)

m = -v/u

3 = -v/u

⇒ v = -3u

Let us now consider Mirror formula

1/v + 1/u = 1/f

1/(-3u) + 1/u = 1/(-10)

⇒ u = -20/3

u = -6.7 cm

So At -6.7cm distance from a concave mirror of focal length 10 cm should an object 2 cm long be placed in order to get an erect image 6 cm tall.

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