At what distance from a concave mirror of focal length 20 cm should an object 2 cm long be placed in order to get an erect image 8 cm tall?
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Given
Focal length of concave mirror (f) = -10 cm
Height of the object (ho) = 2 cm
Height of the image (hi) = 6 cm
We need to find the object distance
So we know that
Magnification m = hi/ho
hi/ho = 6/2
hi/ho = 3 (erect image)
m = -v/u
3 = -v/u
⇒ v = -3u
Let us now consider Mirror formula
1/v + 1/u = 1/f
1/(-3u) + 1/u = 1/(-10)
⇒ u = -20/3
u = -6.7 cm
So At -6.7cm distance from a concave mirror of focal length 10 cm should an object 2 cm long be placed in order to get an erect image 6 cm tall.
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