At what distance from a convex lens of focal
length 2.5 m should a boy stand so that his image
is half his height ?
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Explanation: hope it's helpful to you mark me brainliest and thank my answer please please please please
Magnification=height of the image/height of
the object = -image distance/object distance
Let the actual height be x
=(x/2)/x
=1/2
1/2= -v/u
Using sign convention,
1/2 v/u
U=2v
That is object distance is twice the image
distancee
So, the object should be placed at the centre
of curvature and the image will be formed at
focus.
Object should be placed at centre of
curvature =2(2.5)=5cm
The image will be formed at focus =2.5cm
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