Question

At what distance from center of earth acceleration due to gravity will be 1/4th the valu of g on the surface of earth? (R is radius of earth) ​

Answer 1

Answer:

Hey mate !! here is your answer...

Explanation:

ANSWER

g

′

=g(

R+h

R

)

2

⟹

2

1

=

R+h

R

⟹R+h=

2

R

⟹h=(

2

−1)R=0.414 R