At what distance from equilibrium position is kinetic energy equal to potential energy
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Answer is A/√2
Given condition ,
K.E = P. E
1/2 k( A² - x²) = 1/2 kx²
A² - x² = x²
2x² = A²
x = A/√2
A is amplitude and x is position from equilibrium position. Please mark Brainliest Answer if you liked the answer
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