Question

At what distance from the bullet will strike the ground if a bullet is fried with an initial velocity 250 ms at an angle 30° with the horizontal

Answer 1

Explanation:

A bullet is fired with an initial velocity 300 MS–1 at an angle of 300 with the horizontal. At what distance from the gun will the bullet strike the ground?

This is a simple problem of projectile motion.

Data: Iniatial velocity, u=300 m/s.

Angle of projection , ( theta )= 30^o.

Range, R= ?

Formula: R= 2 u(x)u(y)/g.

u(x) is x- component of initial velocity . u(x) =u cos 30^o=(300)(root 3)/2=259.8 m/s.

u(y) is y- component of initial velocity. u(y)= u sin 30^o= (300)(1/2)=150 m/s.

g is acceleration due to gravity. g=9.8 m/s^2~10m/s^2.

R=(2)(259.8)(150)/10)=7,794 m