At what distance from the centre of the earth its acceleration due to gravity becomes one third only? [Mass and radius of earth = 6x10 24 kg & 6.4x10 6 m resp.]
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Explanation:
mass = 6 x 10^24 kg
radius = 6.4 x 10^6 M
g = 1/3 of original
g = G*M/R^2
Acceleration due to gravity is inversely proportional to square of the distance from the center of earth, therefore ratio of distance (where g will be half) to the earth's radius will be square root of 3.
Thus g will be half at a distance 6.4 x 10^6 x √3, from the center of earth.
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