at what distance of plane mirror of focal length2.5m should a boy stand so that his image has height equal to half of original height
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Let the actual height be x
=(x/2)/x
=1/2
1/2= -v/u
Using sign convention,
1/2 = v/u
u=2v
That is object distance is twice the image distance
So, the object should be placed at the centre of curvature and the image will be formed at focus.
Object should be placed at centre of curvature =2(2.5)=5cm
The image will be formed at focus =2.5cm
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