Question

At what height above the earth's surface does g decrease by 75%

Answer 1

We know that gravity at any height is given as;

g’ = g (1 - 2h/R) —[1]

Decrease by 75% implies that g’ = 25/100g

Substitute In 1,we get

25/100g = g (1 - 2h/R)

25/100 = 1 - 2h/R

2h/R = 1 - 25/100

2h/R = 3/4

h = 3R/8

h = 3*6400/8 (R = 6400KM)

h=3*800=2400km

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