At what height above the Earth's surface does the force of gravity decrease by 10% . assume radius of earth to be 6370 km .
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gravity at surface g=GM/R2
gravity at a height g'=GM/(R+h)2
GM=g×R2
put value of GM in g'
g'=g×R2/(R+h)2
gravity(g') at a height(h) become (R2/(R+h)2) times the gravity at surface.
gravity at a height g'=GM/(R+h)2
GM=g×R2
put value of GM in g'
g'=g×R2/(R+h)2
gravity(g') at a height(h) become (R2/(R+h)2) times the gravity at surface.
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