Question

At what height above the Earth's surface is the acceleration due to gravity 1% less than its value at the surface. Radius of Earth is 6400 km. (Take (1 + x) = 1 - 2r when x << 1)​spam =10 answer report​

Answer 1

Answer:

Answer

Given : g

h

=1% g

s

=0.01 g

s

Using g

h

=g

s

(

R+h

R

)

2

Or 0.01 g

s

=g

s

(

R+h

R

)

2

Or 0.1=

R+h

R

Or 0.1R+0.1h=R

⟹ h=9R

So, K=9