at what height above the Earth's surface the acceleration due to gravity will be 1 9th of its value at the Earth surface
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If g=9.81 is for radius of 6400km of earth
1/9x9.81=1.09
9.81-6400km
1.09-?
X=(1.09x6400)/9.81
=711.111km
6400km-711.111km=5688.888km is the answer
1/9x9.81=1.09
9.81-6400km
1.09-?
X=(1.09x6400)/9.81
=711.111km
6400km-711.111km=5688.888km is the answer
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