Question

At what height above the Earth's surface, the value of g is half of its value on the
Earth's surface?. Given Earth's radius is 6400 km
leave a detailed explanation please..

Answer 1

Answer:

16% is about one sixth. So for the value of g to be reduced by one sixth, since the mass of the Earth, G and the mass being test remain the same, the denominator in the gravity equation must increase by a factor of 6. The distance therefore increases by a factor of √6 = 2.45, so the distance from the center of the Earth will be 2.45 x 6,400 km = 15,680 km from the center of the Earth, or 9,280 km above the surface. This is in the area termed a MEO: medium Earth orbit.

Answer 2

Explanation:

If we use 6,371 km as Earth's radius, the distance above the surface where gravitational acceleration is halved would be 2,639 km.