At what height above the earth surface, the value of ‘g' is half of its volume on earth Surface ? Given its radius is 6.400 km.
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We know, gg′=r2R2
, where g is gravitational force on earth, g' is gravitational force at a height.
Complete step-by-step answer:
Given g' = g2
g’ = gR2r2=g2
⇒r2 = 2R2
⇒r = R2–√ = R + h
⇒h = R (2–√ - 1)
= R (1.414 – 1)
= 0.414R.
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