Question

At what height above the surface of earth acceleration due to gravity reduced by 1% of its value at the earth's surface

Answer 1

concept of gravitation

Answer 2

Answer:

h = 32 km

Explanation:

gh = g/(1 + h/R)^-2

gh = g(1 + h/R)^-2

If h∠∠∠R then

gh = g (1 - 2h/R)

gh = g-2gh/R

gh - g = -2gh/R

Δg/g*100 = -2h/R * 100%

Applicable for small % change,

If Δg/g * 100 = -1

-1 = -2h/6400*10^3 *100

h = 32 * 10^3 * 100

h = 32 km

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